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The relationship between t.0.5 and CAo for a zero order reaction is ____(a) t0.5 = \(\frac{1}{kC_{A0}} \)(b) t0.5 = \(\frac{1}{C_{A0}} \)(c) t0.5 = \(\frac{C_{A0}}{k}\)(d) t0.5 = \(\frac{C_{A0}}{2k}\)The question was asked at a job interview.The doubt is from Rate Data Collection & Analysis topic in chapter Collection and Analysis of Rate Data of Chemical Reaction Engineering

Answer»

Right CHOICE is (d) t0.5 = \(\frac{C_{A0}}{2k}\)

To explain I would SAY: For zero order REACTION, \(\frac{-dC_A}{dt}\) = k. t0.5 = \(\frac{C_{A0}- \frac{C_{A0}}{2}}{k}.\)

HENCE, t0.5 = \(\frac{C_{A0}}{2k}.\)



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