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The relationship between the displacement travelled by a body and the time t is described by the equation `s = A + Bt + Ct^(2) + Dt^(3)`. Where `C = 0.14m//s^(2)` and `D=0.01m//s^(3)`. In what time after motion begins will the acceleration of the body be equal to `1 m//s^(2)?`A. 10 secB. `50 // 3 "sec"`C. 12 secD. 18 sec |
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Answer» Correct Answer - C `S=A+Bt+Ct^(2)+Dt^(3)` `V=B+2Ct+3Dt^(2)` `a=2C+6Dt` `1=2xx0.14+6xx0.01t` t = 12 sec |
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