InterviewSolution
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InterviewSolution
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The relative density of a material of a body is found by weighing it first in air and then in water. If the weight of he body in air is `W_(1) = 8.00 +- N` and the weight in water is `W_(2) = 6.00 +- 0.05 N`, then the relative density `rho_(r ) = W_(1)//( W_(1) - W_(2))` with the maximum permissible eror isA. `4.00 +- 0.62%`B. `4.00 +- 0.82%`C. `4.00 +- 3.2%`D. `4.00+- 5.62%` |
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Answer» Correct Answer - D Relative density `rho_(r ) = (W_(1))/( W_(1) - W_(2)) = ( 8.00) /( 8.00 - 6.00) = 4.00` `( Delta rho_(r))/( rho_(r )) xx 100 = ( Delta W_(1))/( W_(1)) xx 100 + ( Delta (W_(1) - W_(2)))/( W_(1) - W_(2)) xx 100` ` = ( 0.05)/( 8.00) xx 100 + ( 0.05 + 0.05)/( 2) xx 100 = 5.62%` :. `rho_(r ) = 4.00 +- 5.62%` |
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