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The relative density of material of a body is found by weighting it first in air and then in water . If the weight in air is `( 5.00 +- 0.05) N` and the weight in water is `(4.00 +- 0.05) N`. Find the relative density along with the maximum permissible percentage error.A. `5.0+-11%`B. `50+-1%`C. `5.0+-6%`D. `1.25+-5%` |
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Answer» Correct Answer - A Weight in air `(5.00+0.05)N` Weight in water`=(4.00+-0.05)N` Loss of weight in water `=(1.00+-0.1)N` `now relative density`=(weight i n air)/(weight loss i n water)` i.e. `R.D=(5.00+-0.05)/(1.00+-0.1)` Now relative density with max permissible error `=(5.00)/(1.00)+-((0.5)/(5.00)+(0.1)/(1.00))xx100=5.0+-(1+10)%` `=5.0+-11%` |
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