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The relative reactivity of 1^(@), 2^(@), 3^(@), hydrogen's towards chlorination is 1:3.8:5. Calculate the percentage of all mono chlorinated products obtained from 2-methylbutane. |
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Answer» Solution :In 2-methyl butane, there are 9 primary hdyrogen, 2 SECONDARY and 1 tertiaryhydrogen ATOMS. The realtivere activity of `1^(@), 2^(@)` and `3^(@)` hydrogen atoms towards chlorination is 1:3.8:5. RELATIVE amount of product after chlorination = number of hydrogen atom C relative REACTIVITY. `{:("Relative",1^(@) "halide",2^(@) "halide",3^(@) "halide",),("Amount",9 xx 1 = 9,2 xx 3.8 = 7.6,1 xx 5 = 5,):}` Total amount of monochloro product = 9+7.6 +5 = 21.6 Percentage of `1^(@)` monochloro product `= 9 xx 100/21.6 = 41.7%` Percentage of `2^(@)` monochloro product `= 7.6 xx 100//21.6 = 35.2%` Percentage of `3^(@)` monochloro product `= 5 xx 100//21.6 = 23.1%` |
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