InterviewSolution
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InterviewSolution
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the remainder when FX is equal to x cube minus x square + 2 x minus 4 is divided by gx is equal to 1 minus 2 |
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Answer» Explanation:Correct QUESTION :- Find the REMAINDER p(x) = x³ - 6x² + 2x - 4 divided by q(x) = 1 - 2x Answer :- The remainder is - 35/8 when p(x) = x³ - 6x² + 2x - 4 divided by q(x) = 1 - 2x Solution :- p(x) = x³ - 6x² + 2x - 4 divided by q(x) = 1 - 2x FIRST find the ZERO of 1 - 2x To find the zero of 1 - 2x equate it to 0 1 - 2x = 0 - 2x = - 1 x = - 1/-2 x = 1/2 By Remainder theorem p(1/2) is the remainder when p(x) = x³ - 6x² + 2x - 4 divided by q(x) = 1 - 2x p(x) = x³ - 6x² + 2x - 4 Substitute x = 1/2 p(1/2) = (1/2)³ - 6(1/2)² + 2(1/2) - 4 = 1/2³ - 6(1/2²) + 1 - 4 = 1/8 - 6(1/4) + 1 - 4 = 1/8 - 3(1/2) - 3 = 1/8 - 3/2 - 3 Taking LCM = 1/8 - 3(4)/2(4) - 3(8)/1(8) = 1/8 - 12/8 - 24/8 = 1/8 - 36/8 = - 35/8 Therefore the remainder is - 35/8 when p(x) = x³ - 6x² + 2x - 4 divided by q(x) = 1 - 2x |
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