The resistacnce of a conductivity cell filled with 0.01 N KCI at `25^(@)` was found to be 500 `Omega` The specific conductance of 0.01 N KCI at `25^(@)` is `1.41xx10^(-3) Omega^(-) cm^(-1)` The resistance of same cell filled with `0.3 N ZnSO_(4)` at `25^(@)C` was found to be 69 `Omega` Calculate the cell constant equivalent and molar conductivityes of `ZnSO_(4)` solution

The resistacnce of a conductivity cell filled with 0.01 N KCI at `25^(

1.	The resistacnce of a conductivity cell filled with 0.01 N KCI at `25^(@)` was found to be 500 `Omega` The specific conductance of 0.01 N KCI at `25^(@)` is `1.41xx10^(-3) Omega^(-) cm^(-1)` The resistance of same cell filled with `0.3 N ZnSO_(4)` at `25^(@)C` was found to be 69 `Omega` Calculate the cell constant equivalent and molar conductivityes of `ZnSO_(4)` solution
Answer» Cell constant =0.705 `cm^(-1)` Equivalent conductivity `=34.1 Omega^(-1)cm^(-1)eq^(-1)` Molar conductivity `=68.2 Omega^(-1) cm^(-1) mol^(-1)`

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