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The resistance of `1N` solution of acetic acid is `250ohm`, when measured in a cell of cell constant `1.15 cm^(-1)`. The equivalent conductance `(` in `ohm^(-1) cm^(2)eq^(-1))` of `1N` acetic acid isA. `46.0`B. `9.2`C. `18.4`D. `2.3` |
Answer» Correct Answer - A `k=GxxG^(**)=(1)/(T)xxG^(**)` `=(1)/(250)xx1.15` `wedge_(eq)=(kxx1000)/(N)=(1.15xx1000)/(250xx0.1)=46S cm^(2) eq^(-1)` |
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