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The resistance of `1N` solution of acetic acid is `250ohm`, when measured in a cell of cell constant `1.15 cm^(-1)`. The equivalent conductance `(` in `ohm^(-1) cm^(2)eq^(-1))` of `1N` acetic acid isA. `4.6`B. `9.2`C. `18.4`D. `0.023` |
Answer» Correct Answer - a `k=(1)/(R)xxG=GG^(**)=(1)/(250)xx1.15=0.0046S cm^(-1)` `wedge_(eq)=(kxx1000)/(N)=(0.0046xx1000)/(1)=4.6ohm^(-1)cm^(2)eq^(-1)` |
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