1.

The resistance of a 0-2 N solution of an electrolyte in a conductivity cell (cell constant 2.06cm^(-1)) is 100 ohm at 298 K. What are its conductivity and equivalent conductance ?

Answer»

Solution :Conductivity (k) `=("Cell constant")/("Resistance")`
Cell constant `=2.06cm^(-1),R=100Omega`
`k=(2.06)/(100)=2.06xx10^(-2)Omega^(-1)CM^(-1)`
Equivalent CONDUCTANCE,
`Delta=(100xxk)/(C)andC=0.2` g equiv / litre.
`Delta=(1000xx2.06xx10^(-2))/(0.2)`
`=103Omega^(-1)cm^(2)` gram `"equiv"^(-1)`


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