The resistance of a conductivity cell containing 0.001 M KCl solution – InterviewSolution

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1.	The resistance of a conductivity cell containing 0.001 M KCl solution at 298K is 1500 Omega. What is the cell constant if conductivity of 0.001 M KCl solution at 298K is 0.146xx10^(-3)"S "cm^(-1)?
Answer» SOLUTION :CELL constant`=("Conductivity")/("CONDUCTANCE")=`Conductivity`XX`RESISTANCE=(0.146`xx10^(-3)`) S `cm^(-1)xx1500Omega` `=0.219cm^(-1)`

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