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The resistance of a conductivity cell containing 0.001M KCl solution at 298K is 1500Omega .What is the cell constant (inmm^(-1)). If the conductivity of 0.001 M KCl solution is 2 xx 10^(-3) S mm^(-1)

Answer»


SOLUTION :`R = S .(1)/(a) , 1500 = S. (1)/(a)`
CELL CONSTANT = `(1)/(a) = (1)/(5) xx 1500 = 2 xx 10^(-3) xx 1500 = 300 xx 10^(-3) =3 `


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