The resistance of a conductivity cell containing 0.0001 M KCl solution – InterviewSolution

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1.	The resistance of a conductivity cell containing 0.0001 M KCl solution at 298 K is 1500 Ω. What is the cell constant ( in cm−1) if conductivity of 0.0001 M KCl solution at 298 K is 0.146×10−3 S cm−1.
Answer» The resistance of a conductivity cell containing $0.0001 M K C l$ solution at $298 K$ is $1500$ $Ω$ . What is the cell constant ( in $c m^{- 1}$ ) if conductivity of $0.0001 M K C l$ solution at $298 K$ is $0.146 \times 10^{- 3} {S cm}^{- 1}$ .

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