The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3) S cm^(-1)`.

The resistance of a conductivity cell contaning `0.001M KCl` solution

1.	The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3) S cm^(-1)`.
Answer» Cell constant `=("Conductivity")/("Conductance")` `="Conductivity"xx"Resistance"` `=0.146xx10^(-3)" S "cm^(-1)xx1500Omega` `=0.219cm^(-1)`.

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The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3) S cm^(-1)`.

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