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The resistance of a pivoted type galvanometer is `8Omega` and current for full scale deflection on it is `0*01A`. This galvanometer is to be converted into an ammeter of `5A` range. The only shunt available is `0*02Omega`. Find the value of R to be connected in series with the galvanometer coil, figure.

Answer» Correct Answer - `1*98Omega`
`I_g(G+R)=(I-I_g)S`
or `0*01(8+R)=(5-0*01)0*02=4*99xx0*02`
or `R=(4.99xx0.02)/(0.01)-8=9.98-8`
`=1.98Omega`


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