The resistance of a platinum resistance thermometer is found to be 11. 0 ohm when dipped in a triple point cell. When it is dipped in a bath, the resistance is found to be 28.887 ohm. Find the temperature of the bath in ""^(0)C on platinum scale.

The resistance of a platinum resistance thermometer is found to be 11.

1.	The resistance of a platinum resistance thermometer is found to be 11. 0 ohm when dipped in a triple point cell. When it is dipped in a bath, the resistance is found to be 28.887 ohm. Find the temperature of the bath in ""^(0)C on platinum scale.
Answer» SOLUTION :In TERM of triple point of water. `T_(K) = [ 273.16 (R)/(R_(TR)) ] K ` so `T_(K) = 273.16 XX (28.887)/(11.0) = 717.32K` Now as `T_(C) = T_(K) - 273.15` `T_(C) = 717.32 - 273.15 = 444.17^(0)` C