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The resistance of a wire of length 40 m and radius o.25 mm is `10 Omega`. The conductivity of the material of the wire isA. `1xx10^( -7)` mho/mB. `2xx10^(-7)` mho/mC. `2xx10^(7)` mho/mD. `1xx10^(-7)` mho/m |
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Answer» Correct Answer - C `sigma = 1/rho=(l)/(RA)=(40)/(10xx3.14xx625xx10^(-10))` `=2xx10^(7)` mho/m |
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