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The resistance R=v/I where V=(100+-5) and I=(10+-0.2)A. Find the percentage of error |
Answer» V=100+-5 & I= 10+-0.2AR=V/I(∆R/R)×100= (∆V/V)×100 + (∆I/I)×100(∆R/R)×100= (5/100)×100+(0.2/10)×100(∆R/R)×100= (1/20)×100+(1/50)×100(∆R/R)×100= (5+2)%(∆R/R)×100= 7% Answer..... | |