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The resistances corresponding to the lower and the upper fixed points, in a platinum resistance thermometer are 3.59 Omega and 3.65 Omega. What would be the resistance at a temperature equal to the freezing point of mercury(-37^(@)C)?

Answer» <html><body><p></p>Solution :Given : `R_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>) = 3.50 <a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>, R_(100) = 3.65 Omega` and t = `-37^(@)C, R_(t) ` = ?<br/> Using t = `[ (R_(t) - R_(0))/(R_(100) - R_(0)) ] 100^(@)C ` <br/> We have , - `37^(@)C = [ (R_(t) - 3.50)/(3.65 - 3.50) ] 100^(@)` C<br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> R_(t) - 3.50 = - 0.056 "" R_(t) = 3.55 Omega` . <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> ` The required <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a> is `3.55 Omega`</body></html>


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