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The resultant ampiltude of a vibrating particle by the superposition of the two waves `y_(1) = a sin ( omega t + (pi)/(3)) and y_(2) = a sin omega t` is :A. aB. `sqrt(2)_(a)`C. `2a`D. `sqrt(3)_(a)` |
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Answer» Correct Answer - D Resultant amplitude `= 2a cos ((pi//3)/(2)) = sqrt(3a)` |
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