The resultant ot two forces acting at an angle of15^@ ii10 N and is peroendicular to one of the forces. The other force is .

The resultant ot two forces acting at an angle of15^@ ii10 N and is pe

1.	The resultant ot two forces acting at an angle of15^@ ii10 N and is peroendicular to one of the forces. The other force is .
Answer» `20 // SQRT 2 N` `10 // sqrt 3 N` ` 20 N` ` 20 sqrt 3 N` Solution :` 10^@ = A^2 + b^2 +2 AB cos 150^@` ` = A^2 +b^2 - 2 AB ( sqrt 3 //2)` …(i) ` tan 90^@ = ( B sin 150^@)/( A+ B cos ` 15^@) =0` or ` A+B cos 1 50^@ =0` or ` A= B xxsqrt 3//3` …(II) ` From (i), ` 100 = 3/ 4 B^2 + B^@ - ( 3 B^2)/2 = B^2/4` ` or ` B = 20 N`.