The ring of radius 1 m is lying on the surface of liquid. It is lifted from the liquid surface by a force of 4 Newton in such a way that the liquid film in it remains intact. The surface tension of liquid will be-

The ring of radius 1 m is lying on the surface of liquid. It is lifted

1.	The ring of radius 1 m is lying on the surface of liquid. It is lifted from the liquid surface by a force of 4 Newton in such a way that the liquid film in it remains intact. The surface tension of liquid will be-
Answer» <html><body><p>`(1)/( <a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> ) N//m`<br/>`(1)/( <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>) N//m`<br/>`(1)/( <a href="https://interviewquestions.tuteehub.com/tag/3pi-1863811" style="font-weight:bold;" target="_blank" title="Click to know more about 3PI">3PI</a> ) N//m`<br/>`(1)/( 4pi) N//m`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>