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The ring shown in fig. is given a constant horizontal acceleration `(a_(0)=gsqrt(3))`. The maximum deflection of the string from the vertical is `theta_(0)`. Then A. `theta_(0)=30^(@)`B. `theta_(0)=60^(@)`C. at maximum deflection, tension in string is equal to mgD. at maximum deflection, tension in string is equal to `(2mg)/sqrt(3)` |
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Answer» Correct Answer - A::D |
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