The rms velocity of gas molecules of a given amount of a gas at 27∘C and 1.0×105N m−2 pressure is 200 m sec−1. If temperature and pressure are respectively 127∘C and 0.5×105 N m−2, the rms velocity will be:

The rms velocity of gas molecules of a given amount of a gas at 27∘C

1.	The rms velocity of gas molecules of a given amount of a gas at 27∘C and 1.0×105N m−2 pressure is 200 m sec−1. If temperature and pressure are respectively 127∘C and 0.5×105 N m−2, the rms velocity will be:
Answer» The rms velocity of gas molecules of a given amount of a gas at $27^{\circ} C$ and $1.0 \times 10^{5} {N m}^{- 2}$ pressure is $200 {m sec}^{- 1}$ . If temperature and pressure are respectively $127^{\circ} C$ and $0.5 \times 10^{5} {N m}^{- 2}$ , the rms velocity will be:

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The rms velocity of gas molecules of a given amount of a gas at 27∘C and 1.0×105N m−2 pressure is 200 m sec−1. If temperature and pressure are respectively 127∘C and 0.5×105 N m−2, the rms velocity will be:

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