1.

The RMS velocity of nitrogen gas molecules is 'V cm/sec at a certain temperature. When the temperature is doubled, the molecules dissociated into individual atoms. Now the RMS velocity of nitrogen atoms is x V cm/sec. What is the value of 'x'?

Answer»


Solution :`(C_(N_2))/(C_N) = V/(C_N) = SQRT((T_1)/(28) XX 14/(2T_1)) IMPLIES C_N = 2V`


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