1.

The root mean square (r.m.s) speed of oxygen molecules `(O_2)` at a certain temperature T (degree absolute) is V. If the temperature is doubled and oxygen gas dissociates into atomic oxygen, the r.m.s speed remains unchanged.

Answer» `v_("rms")=sqrt((3RT)/(M))`
`v_("rms")propsqrt((T)/(M))`
When oxygen gas dissociates into atomic oxygen, its atomic mass `M` will become half. Temperature is doubled. So, from Eq. (i) `v_("rms")` will become two times.


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