1.

The root mean square velocity of a gas molecule at 100K and 0.5 atm pressure is 106.4 ms^(-1). If the temperature is raised to 400k and the pressure is raised to 2 atm, the root mean square velocity becomes

Answer»

<P>`106.4 ms^(-1)`
`425.6 ms^(-1)`
`212.8 ms^(-1)`
`851.2 ms^(-1)`

Solution :`C_(p ) -C_(V) =R` ( for MONOATOMIC GAS )
`:.C_(p ) = R + C_(v) = R + ( 3)/( 2) R = ( 5)/( 2) R `


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