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The roots of the equation (q − r)x2 + (r − p)x + (p − q) = 0 are A. (r − p)/(q −r), 1/2 B. (p − q)/(q − r), 1 C. (q − r)/(p − q), 1 D. (r − p)/(p − q), 1/2 |
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Answer» Correct option B. (p − q)/(q − r), 1 Explanation: For any equation of form, ax2 + bx + c = 0, if sum of its coefficients is zero then one of its root is 1 and other will be given by c/a. Sum of the coefficients of given equation = q - r + r - p + p - q = 0 Therefore roots are: 1, p - q/q - r |
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