The roots of the equations 2x + 3√x = 2 can be found by solving A

1.	The roots of the equations 2x + 3√x = 2 can be found by solving A) 4x2 – 25x -4 = 0 B) 4x2 – 17x + 4 = 0 C) 4x2 – 25x + 4 = 0 D) 4x2 – 17x -4 = 0
Answer» Correct option is (B) 4x² – 17x + 4 = 0 \(2x-3\sqrt{x}=2\) \(\Rightarrow2x-2=3\sqrt x\) \(\Rightarrow(2x-2)^2=9x\) (By squaring both sides) \(\Rightarrow4x^2-8x+4=9x\) \(\Rightarrow4x^2-17x+4=0\) The roots of the given equation can be found by solving the equation \(4x^2-17x+4=0.\) Correct option is B) 4x² – 17x + 4 = 0

The roots of the equations 2x + 3√x = 2 can be found by solving A) 4x2 – 25x -4 = 0 B) 4x2 – 17x + 4 = 0 C) 4x2 – 25x + 4 = 0 D) 4x2 – 17x -4 = 0

Answer»

Correct option is (B) 4x² – 17x + 4 = 0

\(2x-3\sqrt{x}=2\)

\(\Rightarrow2x-2=3\sqrt x\)

\(\Rightarrow(2x-2)^2=9x\) (By squaring both sides)

\(\Rightarrow4x^2-8x+4=9x\)

\(\Rightarrow4x^2-17x+4=0\)

The roots of the given equation can be found by solving the equation \(4x^2-17x+4=0.\)

Correct option is B) 4x² – 17x + 4 = 0