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The roots of `x^(2) - 2x-1= 0` are `"_____"`.A. `sqrt(2) + 1, sqrt(2) -1`B. `1,sqrt(2)`C. `1+sqrt(2), 1-sqrt(2)`D. `2,1` |
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Answer» Correct Answer - C Given `x^(2) - 2x-1 = 0` `x = (2+-sqrt(4-4xx1xx(-1)))/(2xx1)` `x = (2+-sqrt(8))/(2) = (2+-2sqrt(2))/(2) = 1+-sqrt(2)` `x = 1+sqrt(2)` or `1 - sqrt(2)`. |
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