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The roots of `x^(2) - 2x-1= 0` are `"_____"`.A. `sqrt(2) + 1, sqrt(2) -1`B. `1,sqrt(2)`C. `1+sqrt(2), 1-sqrt(2)`D. `2,1`

Answer» Correct Answer - C
Given `x^(2) - 2x-1 = 0`
`x = (2+-sqrt(4-4xx1xx(-1)))/(2xx1)`
`x = (2+-sqrt(8))/(2) = (2+-2sqrt(2))/(2) = 1+-sqrt(2)`
`x = 1+sqrt(2)` or `1 - sqrt(2)`.


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