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The rotation of the earth about its axis speeds up such that a man on the equator becomes weightness. In such a situation, what would be the duration of one day ? |
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Answer» `2pi SQRT((R)/(g))` `:. omega=sqrt((g)/(R))rArr(2pi)/(T)=sqrt((g)/(R))rArrT=2pi sqrt((R)/(g))` |
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