1.

The rotation of the earth about its axis speeds up such that a man on the equator becomes weightness. In such a situation, what would be the duration of one day ?

Answer»

`2pi SQRT((R)/(g))`
`(1)/(2pi)sqrt((R)/(g))`
`2pi sqrt(Rg)`
`(1)/(2pi)sqrt(Rg)`

Solution :At EQUATOR, `g'=g-R omega^(2)=0`
`:. omega=sqrt((g)/(R))rArr(2pi)/(T)=sqrt((g)/(R))rArrT=2pi sqrt((R)/(g))`


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