1.

The rotational kinetic energy of a body is given byE=1/2I omega^(2). Use this equation to get the dimensional formula of I?

Answer»

Solution :`E=1/2Iomega^(2),I=(2E)/(omega^(2))`
Dimensional formula of I= Dimensional formula of `[E/(omega^(2))]`
`[I]=([ML^(2)T^(-2)])/([T^(-1)]^(2)=[ML^(2)]`


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