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The rubber cord of a catapult has a cross sectional area 1"mm"^(2) and total unstretched length 10cm. It is stretched to 12cm and then released to project a missile of mass 5gm. Taking Y for rubber 5 xx 10^(8) "Nm"^(-2) calculate the velocity of projection.... |
Answer» <html><body><p>`10 "ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> "ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> "ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> "ms"^(-1)`</p>Answer :B</body></html> | |