The rusting of iron takes place as follows `2H^(+)+2e^(-)+1//2O_(2)rarrH_(2)O(l), E^(@)=+1.23 V` `Fe^(2+)+2e^(-)rarrFe(s), E^(@)=-0.44V` Calculate `DeltaG^(@)` for the net processA. `-322 kJ mol^(-1)`B. `-161 kJ mol^(-1)`C. `-152 kJ mol^(-1)`D. `-76 kJ mol^(-1)`

The rusting of iron takes place as follows `2H^(+)+2e^(-)+1//2O_(2)rar

1.	The rusting of iron takes place as follows `2H^(+)+2e^(-)+1//2O_(2)rarrH_(2)O(l), E^(@)=+1.23 V` `Fe^(2+)+2e^(-)rarrFe(s), E^(@)=-0.44V` Calculate `DeltaG^(@)` for the net processA. `-322 kJ mol^(-1)`B. `-161 kJ mol^(-1)`C. `-152 kJ mol^(-1)`D. `-76 kJ mol^(-1)`
Answer» Correct Answer - A `Fe(s)rarrFe^(2+)+2e^(-), " "E^(@)=0.44 V` `(2H^(+)+2e^(-)+1//2O_(2)rarrH_(2)O(l), " "E^(@)=+1.23 V)/(Fe(s) +2H^(+)+1//2O_(2)rarrFe^(2+)+H_(2)O,)` `E_("cell")^(@)=0.44+1.23=1.67 V` `thereforeDeltaG^(@)="-nF " E_("cell")^(@)=-2xx96500xx1.67=-322 kJ`.

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