1.

The rustingof iron takesplace as follows 2H^(opluse)+2e^(-)+1/2 O_(2)rarrH_(2)O(l),E^(-)=+1.23 V Fe^(2+)(aq)+2e^(-)+2e^(-)rarrFe(S),E^(-1)=-0.44V triangleG^(-) forthe netprocess is

Answer»

`-322 kJ mol^(-1)`
`-152 kJ mol^(-1)`
`-76 kJ mol^(-1)`
`-161 kJ mol^(-1)`

Solution :At CATHODE `2H^(opluse)(aq)+2E^(-)+1/2 O_(2)(G)rarrH_(2)O(l)`
At ANODE `Fe(s) rarr Fe^(2+) rarr Fe^(+) (aq) +2e^(-)`
`triangle G_(2)^(-) =- 2xxFe^(-) =(-) 2xxF(0.44)`
`2H^(+opluse)(aq)+1/2 O_(2) +Fe(s)rarrH_(2)O(l)+Fe^(2+) (aq)`
`triangle G_("net")^(-) =[-2F(1.123 )] +(-) 2F(0.44) ] =- 322.3 kJ "mol"^(-)`


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