The salt Al(OH)_(3) is involved in the following two equilibria, Al(OH)_(3(s)) hArr Al_((aq))^(3+) + 3OH_((aq))^(o.), ksp Al(OH)_(3(s)) + OH_((aq))^(-) hArr [Al(OH)_(4)^(-)]_((aq)), kc Which of the following relationship is correct at which solubility is minimum?

The salt Al(OH)_(3) is involved in the following two equilibria, Al(O

1.	The salt Al(OH)_(3) is involved in the following two equilibria, Al(OH)_(3(s)) hArr Al_((aq))^(3+) + 3OH_((aq))^(o.), ksp Al(OH)_(3(s)) + OH_((aq))^(-) hArr [Al(OH)_(4)^(-)]_((aq)), kc Which of the following relationship is correct at which solubility is minimum?
Answer» `[OH^(-)] = ((Ksp)/(Kc))^(1//3)` `[OH^(-)] = ((Kc)/(Ksp))^(1//4)` `[OH^(-)] = sqrt(((Ksp)/(Kc))^(1//4))` `[OH^(-)] = ((3Ksp)/(Kc))^(1//4)` Solution :`S= [Al_((aq))^(+3)] + [AL(OH)_(4(aq))]^(-)` `S = (Ksp)/([OH^(-)]^(3) + Kc[OH^(-)]` for MINIMUM SOLUBILITY `(ds)/(d(OH^(-))) = 0` `:. - (Ksp XX 3 )/([OH^(-)]^(4)) + Kc = 0,[OH^(-)] = ((3Ksp)/(Kc))^(1//4)`