1.

The same quantity of electricity that liberated 2.158 g silver was passed through a solution of a gold salt and 1.314 g of gold was deposited. The equivalent mass of silver is 107.9. Calculate the equivalent mass of gold. What is the oxidation state of gold salt ? (At. mass of gold =197)A. 16 AB. 26.5 AC. 56 AD. 100 A

Answer» Correct Answer - A
i= ? W = 39.49 , t = 3600 sec .
E for `Au^(3+) = (197)/(3) = 65.66`
`W = (E)/(96,500) xx ixxt`
`i= (W xx 96,500)/(Exxt) = (39.4 xx 96,500)/((197)/(3) xx 3,600) = 16 A`


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