The scalar product \(\vec A\). \(\vec B\) is equal to-(a) \(\vec A\, + \, \vec B\)(b) \(\vec A . \vec B\)(c) AB sin θ(d) (\(\vec A\) x \(\vec B\))

The scalar product \(\vec A\). \(\vec B\) is equal to-(a) \(\vec A\

1.	The scalar product \(\vec A\). \(\vec B\) is equal to-(a) \(\vec A\, + \, \vec B\)(b) \(\vec A . \vec B\)(c) AB sin θ(d) (\(\vec A\) x \(\vec B\))
Answer» Correct answer is (b) \(\vec A . \vec B\)

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The scalar product \(\vec A\). \(\vec B\) is equal to-(a) \(\vec A\, + \, \vec B\)(b) \(\vec A . \vec B\)(c) AB sin θ(d) (\(\vec A\) x \(\vec B\))

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