The schrodinger wave equation for hydrogen atom is Psi_2 = (1)/(4sqrt(2pi))((1)/(a_0))^(3//2) (2-(r)/(a_0))e^(-r//a_0) where a_0 is Bohr.s radius. If the radial node in 2s be at r_0 would be equal to

The schrodinger wave equation for hydrogen atom is Psi_2 = (1)/(4sqrt(

1.	The schrodinger wave equation for hydrogen atom is Psi_2 = (1)/(4sqrt(2pi))((1)/(a_0))^(3//2) (2-(r)/(a_0))e^(-r//a_0) where a_0 is Bohr.s radius. If the radial node in 2s be at r_0 would be equal to
Answer» `(a_0)/(2)` `2a_0` `sqrt2 a_0` `(a_0)/(sqrt2)` Solution :At RADIAL NODE `varphi^2 = 0,2 - R/(a_0) =0 , r=2a_0`