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The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L meter long. The length of the open pipe will be

Answer» <html><body><p>`L/2m`<br/>`4Lm`<br/>`Lm`<br/><a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a> m</p>Solution :(i) For open pipe of <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> L. second overtone `=(<a href="https://interviewquestions.tuteehub.com/tag/3v-310794" style="font-weight:bold;" target="_blank" title="Click to know more about 3V">3V</a>)/(2L.)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) For closed pipe of length L first overtone `= (3v)/(4L)` <br/> As per the <a href="https://interviewquestions.tuteehub.com/tag/statement-16478" style="font-weight:bold;" target="_blank" title="Click to know more about STATEMENT">STATEMENT</a>, `(3v)/(2L.) = (3v)/(4L)` <br/> `therefore L. = 2L`</body></html>


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