the secreenning constant of last electron of which element will ne max

1.	the secreenning constant of last electron of which element will ne maximum :
Answer» 24 18 23 22 Solution :`""_(24)CR^(+5)implies (1s^(2))(2s^(2)2p^(6))(3s^(2)3P^(6))(3D^(1))` ` sigma=1xx(18)=18`

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