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The section contains one question. Each question contains statements given in two columns which have to be matched . The statements in Column I are labelled A, B, C and D , while the statements in Column II are labelled p,q, r, s and t. Any given statement in Column I can have correct matching with ONE OR MORE statements (s) in Column II . The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example: If the correct matches are A-p, s and t, B-q and r, C-p and q, and D-s and t, then the correct darkening of bubbles will look like the following . Match the following : |
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Answer» <P> USING phenolphthalein INDICATOR . eq of `Na_(2)CO_(3)` will react. ` :. 1^(st)` titre value `Na_(2) CO_(3) + HCl to NaHCO_(3)+ NaCl` ` :. 1^(st) ` titre value = eq of`Na_(2)CO_(3)` Using methyl orange indicator : eq of `NaHCO_(3) ` produced from `Na_(2)CO_(3)` & eq of `NaHCO_(3)` present will react : `NaHCO_(3) + HCl to NaCl + H_(2)O + CO_(2)` ` :. 2^(nd) ` titre value = eq of `Na_(2)CO_(3) + " eq of " NaHCO_(3)` . ` A to r, s` (B) `Na_(2)CO_(3) + NaOH` Using phenolphthalein indicator : `Na_(2)CO_(3)+HCl to NaHCO_(3) + NaCl` ` NaOH + HCl to NaCl + H_(2)O` ` :. 1^(st) ` titre value = eq of `Na_(2)CO_(3) + ` eq of NaOH . Using methyl orange indicator : `NaHCO_(3) + HCl to NaCl + H_(2)O + CO_(2)` (produced from `Na_(2)CO_(3)`) `2^(nd) ` titre value = eq of `Na_(2)CO_(3)` ` B to q,t ` (C ) `Na_(2)C_(2)O_(4) + H_(2)C_(2)O_(4)` Using `NaOH ` & phenolphthalein indicator : ` H_(2)C_(2)O_(4) + NaOH to Na_(2)C_(2)O_(4) + H_(2)O` ` :. 1^(st)` titre value of NaOH =eq. of `H_(2)C_(2)O_(4)` Using `KMnO_(4)` in acidic MEDIUM : Using `KMnO_(4)` in acidic medium : `KMnO_(4) + Na_(2)C_(2)O_(4) + H^(+) to CO_(2) + Mn^(2+) + H_(2)O + Na^(+)` `2^(nd)` titre value will give the eq of total `Na_(2)C_(2)O_(4) & H_(2)C_(2)O_(4)` but in different n-factor value . The estimation of `Na_(2)C_(2)O_(4)` can be done by the difference in moles of total `Na_(2)C_(2)O_(4) + H_(2)C_(2)O_(4) " in " 2^(nd) ` titration & moles of `H_(2)C_(2)O_(4) " in " 1^(st)` titration . But difference in `1^(st) & 2^(nd)` titre value will not give the estimation of `1^(st)` constituent. ` C to P ` (D) `H_(2)CO_(3) + NaHCO_(3)` Using NaOH & methyl orange indicator : `H_(2)CO_(3) + NaOH to NaHCO_(3) + H_(2)O` `1^(st)` titre value will give the estimation of `1^(st)` constituent. Using `NaOH` & phenolphthalein indicator : `NaHCO_(3) + NaOH to Na_(2)CO_(3) + H_(2)O` `uparrow` `(NaHCO_(3) " present + " NaHCO_(3) " preduced from " H_(2)CO_(3))` Difference in `2^(nd) & 1^(st)` titre value will give the estimation of `2^(nd)` constituent . `D to s, t` |
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