The self ionisation constant for pure formic acid `K=[HCOOH_(2)^(+)][HCOO^(-)]` has been estimated as `10^(-6)` at room temperature .The density of formic acid is `1.15g//cm^(3)` .What percentage of formic acid molecules in pure fomic acid are converted to formation ion?A. `0.002%`B. `0.004%`C. `0.006%`D. `0.008%`

The self ionisation constant for pure formic acid `K=[HCOOH_(2)^(+)][H

1.	The self ionisation constant for pure formic acid `K=[HCOOH_(2)^(+)][HCOO^(-)]` has been estimated as `10^(-6)` at room temperature .The density of formic acid is `1.15g//cm^(3)` .What percentage of formic acid molecules in pure fomic acid are converted to formation ion?A. `0.002%`B. `0.004%`C. `0.006%`D. `0.008%`
Answer» Given density of formic acid =`1.15g//cm^(3)` :.Weight of formic acid in `1` litre solution =`1.15xx10^(3)g` thus `[HCOOH]=(1.15xx10^(3))/(46)=25M` since in case of auto ionisation `[HCOOH_(2)^(+)]=[HCOO^(-)]` and `[HCOO^(-)][HCOOH_(2)^(+)]=10^(-6)rArr [HCOO^(-)]=10^(-3)` Now `%` dissociation of `HCOOH=([HCOO^(-)]xx100)/([HCOOH])=(10^(-3))/(25)xx100=0.004%`

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