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The sequence of anaerobic respiration in our muscle cells during heavy exercise is :(a) Glucose \(\overset{\text{Cytoplasm}}{\longrightarrow}\) Pyruvate \(\overset{\text{Muscle cells}}{\longrightarrow}\) Lactic acid + Energy(b) Glucose \(\overset{\text{Mitochondria}}{\longrightarrow}\) Pyruvate \(\overset{\text{Muscle cells}}{\longrightarrow}\) Carbon dioxide + Water(c) Glucose \(\overset{\text{Cytoplasm}}{\longrightarrow}\) Pyruvate \(\overset{\text{Muscle cells}}{\longrightarrow}\) Ethanol + Carbon dioxide(d) Glucose \(\overset{\text{Mitochondria}}{\longrightarrow}\) Pyruvate \(\overset{\text{Muscle cells}}{\longrightarrow}\) Ethanol + Lactic acid |
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Answer» Correct answer is (d) Glucose \(\overset{\text{Mitochondria}}{\longrightarrow}\) Pyruvate \(\overset{\text{Muscle cells}}{\longrightarrow}\) Ethanol + Lactic acid Ethanol and lactic acid are the products formed by the an aerobic respiration. here, no CO2 or water is produced. the glucose does not break completely thus less energy is released in this types of respiration. |
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