1.

The set of real values of t∈[−π2,π2] satisfying 2sint=1−2x+5x23x2−2x−1, ∀x∈R−{−13,1} lies in the interval

Answer»

The set of real values of t[π2,π2] satisfying 2sint=12x+5x23x22x1, xR{13,1} lies in the interval



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