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The set of real values of t∈[−π2,π2] satisfying 2sint=1−2x+5x23x2−2x−1, ∀x∈R−{−13,1} lies in the interval |
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Answer» The set of real values of t∈[−π2,π2] satisfying 2sint=1−2x+5x23x2−2x−1, ∀x∈R−{−13,1} lies in the interval |
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