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The set of values of p for which the roots of the equation `3x^2 +2x + p(p-1) =0` are of opposite signs is: |
Answer» Let one root is `alpha`. So, second root will be `-alpha`. `:.` Sum of roots `= alpha-alpha = 0` `:.` Product of roots `= -alpha^2` It means product of rootsis less than `0`. Product of roots in the given equation is `(p(p-1))/3`. `:. (p(p-1))/3 lt 0` `=> (p(p-1)) lt 0` `:.p in ]0,1[` |
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