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The set of values of x for which [x2+12]+[x2+22]+[x2+32]+⋯[x2+202]=140 is/are(where [.] is greatest integer function) |
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Answer» The set of values of x for which [x2+12]+[x2+22]+[x2+32]+⋯[x2+202]=140 is/are |
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