The shadow of a pole standing on a level around is found to be 45 m longer when the Sun's altitude is 30^(@) than when it was 60^(@). Determine the height of the pole. [Given sqrt(3) = 1.73]

The shadow of a pole standing on a level around is found to be 45 m lo

1.	The shadow of a pole standing on a level around is found to be 45 m longer when the Sun's altitude is 30^(@) than when it was 60^(@). Determine the height of the pole. [Given sqrt(3) = 1.73]
Answer» Solution :Solution `(x-45)/(H) = COT 30^(@) RARR h = (x+45)/(cot 30^(@))` `x/h = cot 60^(@)` SUBSTITUTING the value of x in the above equation `h = (h cot 60^(@) + 45)/(cot 30^(@))` `h cot 30^(@) = h cot 60^(@) + 45` `h = (45)/(cot 30^(@) - cot 60^(@)) = (45)/(sqrt(3) - (1)/(sqrt(3))) = 38.97` m