1.

The shape of an ancient water clock jug is such that water level descends at a constant rate at all time. If the water level falls by 4cm every hour, determine the shape of the jar, i.e. specify x as a function of y. The radius of drain hole in 2mm and can be assumed to be very small compared to x.

Answer»


Solution :`a sqrt(2gy)=pix^(2)(-(dy)/(DT))`
Here, `-(dy)/(dt)=(4XX10^(-2))/(3600)=1.11xx10^(-5) m//s`
`a=pir^(2)=pi (2XX10^(-3))^(2)`
`=1.26xx10^(-5)m^(2)`
substituting these values in Eq, (i) we have
`(1.26xx10^(-5))sqrt(2xx9.8xxy)=pi (1.11xx10^(-5))x^(2)`
or, `y=0.4x^(4)`
This is the desired x-y relation.


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