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The shape of methyl carbocation is likely to be |
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Answer» tetrahedral `-overset(|) underset(|)C-Z to -overset(|) underset(|)C+Z^(-)` In `CH_(3)^(+)`, the carbon ATOM is `SP^(2)`- hybridised , so the carbon atom used `sp^(2)` hybrid orbitals to formthree `SIGMA` bonds. A empty p-orbitalis symmetrically above and below the plane of three sigma bonds. This empty p-orbital makes the carbon atom electron-defincient (eelectrophile). The three `sp^(2)` hybrid orbitalsare directed towards the CORNERS of a equilateral triangle. Hence, the shape of `CH_(3)^(+)` is likely to be planar. |
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